libXML now returnes info why XML is not valid (#218)
Co-authored-by: Adam Bem <adam.bem@zoho.eu> Reviewed-on: #218 Reviewed-by: Mikolaj Widla <widlam@noreply.example.com>
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@@ -77,10 +77,12 @@ def xsd(source: str, xsd: str) -> bool:
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document_input = BytesIO(source.encode("utf-8"))
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xml = etree.parse(document_input).getroot()
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if xml_schema.validate(xml):
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return "XML is valid."
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else:
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return "XML is NOT valid."
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try:
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xml_schema.assertValid(xml)
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return "XML is valid"
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except etree.DocumentInvalid as e:
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return str(e)
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def xslt(source: str, xslt: str) -> str:
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